Cs50 Tideman Solution [INSTANT × PACK]

// Allocate memory for voters and candidates *voters_prefs = malloc(*voters * sizeof(voter_t)); candidate_t *candidates_list = malloc(*candidates * sizeof(candidate_t));

// Function to check for winner int check_for_winner(candidate_t *candidates_list, int candidates) { // Check if any candidate has more than half of the first-place votes for (int i = 0; i < candidates; i++) { if (candidates_list[i].votes > candidates / 2) { return i + 1; } } return -1; }

// Structure to represent a candidate typedef struct candidate { int id; int votes; } candidate_t; Cs50 Tideman Solution

3 3 1 2 3 1 3 2 2 1 3 This input represents an election with 3 voters and 3 candidates. The output of the program should be:

candidate_t *candidates_list = malloc(candidates * sizeof(candidate_t)); for (int i = 0; i < candidates; i++) { candidates_list[i].id = i + 1; } // Allocate memory for voters and candidates *voters_prefs

printf("The winner is: %d\n", winner);

// Read in voter preferences for (int i = 0; i < *voters; i++) { (*voters_prefs)[i].preferences = malloc(*candidates * sizeof(int)); for (int j = 0; j < *candidates; j++) { scanf("%d", &(*voters_prefs)[i].preferences[j]); } } } i++) { if (candidates_list[i].votes &gt

The winner is: 1 This indicates that candidate 1 wins the election.